find the sum of all whole numbers n such that when 60 is divided by n it gives a remainder of 4

a. 120

b. 113

c. 57

d. 56

## answer:

**d.**** ****5****6**

**explanation****:**

To solve this problem, we need to find all the factors of 60 that leave a remainder of 4 when divided into 60.

First, we can list out the factors of 60:

1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60

Then, we can divide 60 by each of these factors and see which ones leave a remainder of 4:

60 ÷ 5 = 12 remainder 0

60 ÷ 10 = 6 remainder 0

60 ÷ 15 = 4 remainder 0

60 ÷ 20 = 3 remainder 4

60 ÷ 30 = 2 remainder 0

Therefore, the only factors that leave a remainder of 4 are 20 and 40.

The sum of these two factors is:

20 + 40 = 60

So the answer is d. 56 is not a valid answer since it is not the sum of any factors of 60.