Find the sum!
Costumers entering a department store were given a ticket with a number. The first costumer got 0100, the second got 0102, the third costumer got 0104, and so on. The number on the ticket formed and arithmetic sequence. If the sequence continues, what number will the 25th costumer have? what is t80? Who among the costumers got the ticket number 0500? If the last costumer got number 1064, how many costumers enter the store?
Answer:
0148
0258
201st costumer
483
Step-by-step explanation:
an = a1 + (n-1)d
an = 100 + (25-1)2
an= 100+ 48
a25 = 148
t80 or a80 = 100 + (80-1)2
a80 = 100 + 158
a80=258
0500 = 100 + (n-1)2
0500 = 100 + 2n – 2
0500 = 98 + 2n
-98 + 0500 = 2n
402 = 2n
2 2
201 = n
1064 = 100 + (n-1)2
1064 = 98 +2n
-98 + 1064 = 2n
2 2
483 = n
